class Solution:
def simplifyPath(self, path: str) -> str:
stack = ["/",]
path = path.split("/")
for i in range(len(path)):
if(path[i] == "." or path[i] == ""):
continue
else:
if(path[i] == ".."):
if(len(stack) == 1):
continue
else:
stack.pop()
stack.pop()
else:
stack.append(path[i])
stack.append("/")
stack = "".join(stack)
if(len(stack) == 1):
return "/"
else:
return stack[:len(stack) -1]
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779. K-th Symbol in Grammar | 701. Insert into a Binary Search Tree |
429. N-ary Tree Level Order Traversal | 739. Daily Temperatures |
647. Palindromic Substrings | 583. Delete Operation for Two Strings |
518. Coin Change 2 | 516. Longest Palindromic Subsequence |
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445. Add Two Numbers II | 442. Find All Duplicates in an Array |
437. Path Sum III | 436. Find Right Interval |
435. Non-overlapping Intervals | 406. Queue Reconstruction by Height |
380. Insert Delete GetRandom O(1) | 332. Reconstruct Itinerary |
368. Largest Divisible Subset | 377. Combination Sum IV |
322. Coin Change | 307. Range Sum Query - Mutable |
287. Find the Duplicate Number | 279. Perfect Squares |
275. H-Index II | 274. H-Index |
260. Single Number III | 240. Search a 2D Matrix II |